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Question

If 2,8 are the roots of x2+ax+β=0 and 3,3 are the roots of x2+αx+b=0 then find the roots of x2+ax+b=0.

A
1,9
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B
1,9
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C
2,8
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D
2,8
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Solution

The correct option is B 1,9
Given 2,8 are the roots of the equation x2+ax+β=0.
Then form the relation of roots and co-efficients we get,
a=10 and β=16........(1).
Also given 3,3 are the roots of the equation x2+αx+b=0.
Then from the relation between the roots and co-efficients we get,
α=6 and b=9.......(2).
Using values of a and b the equation x2+ax+b=0 will take the form,
x210x+9=0
or, (x1)(x9)=0
or, x=1,9.
The required roots are 1,9

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