Question

$If289={17}^{x\frac{1}{5}},thenx=?$

• A. $16$
• B. $83$
• C. $32$
• D. $\frac{2}{5}$
• E. None of the above

Answer 1

The correct option is E None of the above

$Here,{17}^{x\frac{1}{5}}=289$
$\Rightarrow (17{)}^{x+\frac{1}{5}}=(17{)}^2$ $[\because 289={17}^2]$
$\Rightarrow x+\frac{1}{5}=2$
$\Rightarrow x=2-\frac{1}{5}=\frac{9}{5}$