Question

If $2a+3b–5c=0,$ then the ration in which $c$divides $AB$ is?

• A. $3:2$ internally
• B. $3:2$ externally
• C. $2:3$ internally
• D. $2:3$externally

Answer 1

The correct option is C

$2:3$ internally

Explanation for the correct options:

Finding the ratio.

Given Data,

$2a+3b–5c=0$

$\Rightarrow$ $2a+3b=5c$

$\Rightarrow$ $\left(\frac{2}{5}\right)a+\left(\frac{3}{5}\right)b=c$

$\Rightarrow$$\frac{2a+3b}{5}=c$

$\Rightarrow$$\frac{2a+3b}{2+3}=c$

So, point $c$divides the line $AB$ internally in the ration of $2:3.$

Hence, Option(C) is correct.