If 2a =3b =6c then show that c = ab÷a+b
If 2^a =3^b =6^c , then prove that c = ab / a+b
there may be other ways to solve it. and my ans is correct but u may not get full marks. i m not sure.
let 2^a =3^b =6^c = d
so, 2^a = d
=>d^(1/a) = 2--------(1)
and 3^b =d
=>d^(1/b)=3---------(2)
and also 6^c=d
=>d^(1/c)=6---------(3)
we know that 6= 2X3,
6= 2X3----(4)
now put value of 2, 3 and 6 from equation 1, 2 and 3 we get
d^(1/a) × d^(1/b) = d^(1/c)
d^(1/a +1/b) = d^(1/c)
so, 1/c = 1/a+1/b =>1/c= (b+a)/ab
=> c= ab/a+b hence proved.