If 2a+12a=8, then find 4a2+14a2.
Applying the formula, (a+b)2=a2+b2+2ab(2a+12a)2=2a2+(12a)2+2×2a×12a=4a2+14a2+2=>4a2+14a2=(2a+12a)2−2Substituting 2a+12a=8, =>4a2+14a2=82−2=64−2=62
If 2a+12a=8, find :
(i) 4a2+14a2
(ii) 16a4+116a4
Factorise 2a7−128a