If 2a−3a=1, then, the value of 8a3−27a3 is not equal to 18 .
True
False
Given: 2a−3a=1
⇒(2a−3a)3=1
⇒(2a)3−33a3−3×2a×3a×(2a−3a)=1
⇒8a3−27a3−18×1=1
⇒8a3−27a3=1+18=19
Therefore, the value is 19 and not 18.
Hence the statement is true.
If 2a−3a=1, then, find the value of 8a3−27a3
If tan2A=cot(A−18∘), then value of A is ((A - 18) & 2A are acute angle)