If 2ax2−x2+2 has a remainder 2 when divided by x−3, then what will be the reciprocal of a?
A
1`
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B
12
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C
112
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D
−12
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Solution
The correct option is A12 Replace x as 3 in the expression: 2ax2−x2+2 =2a(3)2−32+2 =18a−32+2 =36a+12 So, the remainder is 36a+12, Now substitute the value of remainder as 2. 36a+12=2 36a+1=4 36a=3 a=112 The reciprocal of a=12.