Question

If $2f\left(x\right)-3f\left(\frac{1}{2}\right)=x^2,x$ is not equal to zero, then f(2) is equal to.

• A. $\frac{13}{8}$
• B. $-\frac{5}{8}$
• C. -1
• D. none of these

Answer 1

Answer: (A)

$\frac{13}{8}$

Putting $x=\frac{1}{2}$

$-f\left(\frac{1}{2}\right)=\frac{1}{4}$

$f\left(\frac{1}{2}\right)=-\frac{1}{4}$

$2f\left(2\right)-3\times (-\frac{1}{4})=4$

$2f\left(2\right)=-\frac{3}{4}+4$

$f\left(2\right)=\frac{13}{8}$