wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If 2f(xy)=(f(x))y+(f(y))x x,yR and f(1)=3, then the value of 10r=1f(r) is equal to

A
32(3101)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
32(391)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12(3101)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12(391)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 32(3101)
Given, 2f(xy)=(f(x))y+(f(y))x and f(1)=3
Put y=1
2f(x)=f(x)+(f(1))x
f(x)=3x

10r=1f(r)
=10r=13r=3+32+33++310=32(3101)
( For G.P., Sn=a(rn1)r1)

flag
Suggest Corrections
thumbs-up
6
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Geometric Progression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon