If 2kg mass is rotating on a circular path of radius 0.8m with angular velocity of 44 rad/sec. If radius of the path becomes 1m then what will be the value of angular velocity?

28.16 rad/sec

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19.28 rad/sec

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8.12 rad/sec

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35.26 rad/sec

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Solution

The correct option is D 28.16 rad/sec
Angular momentum conservation yields: $ω_{2} = \frac{I_{1} ω_{1}}{I_{2}}$ .
$\frac{I_{1}}{I_{2}} = \frac{{r_{1}}^{2}}{{r_{2}}^{2}}$

Substituting the values, we get $ω_{2} = 0.64 \times 44 = 28.16 r a d / s$ .

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If 2kg mass is rotating on a circular path of radius 0.8m with angular velocity of 44 rad/sec. If radius of the path becomes 1m then what will be the value of angular velocity?

The correct option is D 28.16 rad/secAngular momentum conservation yields: ω2=I1ω1I2.I1I2=r12r22Substituting the values, we get ω2=0.64×44=28.16rad/s.

The correct option is D 28.16 rad/sec
Angular momentum conservation yields: $ω_{2} = \frac{I_{1} ω_{1}}{I_{2}}$ .
$\frac{I_{1}}{I_{2}} = \frac{{r_{1}}^{2}}{{r_{2}}^{2}}$

Substituting the values, we get $ω_{2} = 0.64 \times 44 = 28.16 r a d / s$ .