If 2L, 4L and 6L of three separate solutions of concentrations 1M, 2M and 3M, respectively, are mixed together then what is the concentration of the resultant mixture?

2.333M

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6.000M

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3.333M

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1.500M

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Solution

The correct option is A 2.333M
Given,
$V_{1} = 2 L$
$V_{2} = 4 L$
$V_{3} = 6 L$
$M_{1} = 1 M$
$M_{2} = 2 M$
$M_{3} = 3 M$
Resultant concentration, $M_{B} = \frac{(M_{1} V_{1} + M_{2} V_{2} + M_{3} V_{3})}{(V_{1} + V_{2} + V_{3})}$
$M_{B} = \frac{(2 \times 1 + 4 \times 2 + 6 \times 3)}{(2 + 4 + 6)} = 2.333 M$ .

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