Question

If 2nd term is -15 and 3rd term
$2^{nd}=-15$
$3^{rd}=10$ $\therefore$ a+16 =

Answer 1

$T_n=a+(n-1)d$

$T_2=a+d=-15$..........(1)

$T_3=a+2d=10$.......(2)

(2)-(1) gives,

$d=25$

$\therefore a=-15-25=-40$

Given,

$a+16=-40+16=-24$