Question

If $(2p-1),$ 7 and 3p are in AP, find the value of p.

Answer 1

Let (2p−1), 7 and 3p be three consecutive terms of an AP.
Then 7 − (2p −1) = 3p − 7
⇒ 5p = 15
⇒ p = 3​
∴ When p = 3, (2p−1), 7 and 3p form three consecutive terms of an AP.