If $2 s, 2 p_{x}, 2 p_{y}, 2 p_{z}$ orbitals are hybridized, then the number of hybrid orbitals will be ______.

one

No worries! We‘ve got your back. Try BYJU‘S free classes today!

two

No worries! We‘ve got your back. Try BYJU‘S free classes today!

three

No worries! We‘ve got your back. Try BYJU‘S free classes today!

four

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D four
$∙$ Two or more orbitals of comparable energy intermix to form same number of hybrid orbitals having equal energies and same shape. Hence, number of hybrid orbitals = Number of orbitals undergoing hybridisation.

$∙$ Here, four orbitals namely $2 s$ , $2 p_{x}$ , $2 p_{y}$ , $2 p_{z}$ participate in hybridisation. Therefore four new ${s p}^{3}$ hybrid orbitals are formed.

Suggest Corrections

Similar questions

2 s, 2 p_{x}, 2 p_{y}, 2 p_{z}

If the following orbitals are hybridized, then the number of hybrid orbitals will be:
$2 s$ , $2 p_{x}$ , $2 p_{y}$ , $2 p_{z}$

σ (1 s) < σ^{*} (1 s) < σ (2 s) < σ^{*} (2 s) < [π (2 p_{y}) π (2 p_{z})] < σ (2 p_{x}) < [π^{*} (2 p_{y}) π^{*} (2 p_{z})] < σ^{*} (2 p_{x})

2 p_{x}, 2 p_{y}

2 p_{z}

x -

1 s

2 s

1 s

2 p_{x}

2 p_{y}

2 p_{y}

1 s

2 s

Join BYJU'S Learning Program