If $2 t, t + 10,$ and $3 t + 2$ are three consecutive terms of an AP, then find the value of $t .$

3

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6

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8

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22

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Solution

The correct option is A $6$
$2 t, t + 10, 3 t + 2 a r e i n A . P . 2 (t + 10) = 2 t + 3 t + 2 2 t + 20 = 5 t + 2 18 = 3 t t = 6$

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