If 2 x2-3 x y-y2-x-2 y-8-0 then d y-d x-A- 3 y-4 x-1-2 y-3 x-2B- 3 y-4 x-1-2 y-3 x-2C- 3 y-4 x-1-2 y-3 x-2D- 3 y-4 x-1-2 y-3 x-2

The correct option is A 2x^2 3xy+y^2+x+2y 8=0 ⇒ 4x 3(y+xy^1)+2y.y^1+1+2.y^1=0 ⇒ y^1=3y 4x 1/2y 3x+2 ...

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Identity (x+y)^2

If 2 x2-3 x y...

Question

$I f 2 x^{2} - 3 x y + y^{2} + x + 2 y - 8 = 0 t h e n \frac{d y}{d x} =$

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Solution

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Similar questions

\frac{d y}{d x} = \frac{4 x - 3 y}{3 x - 2 y}

(2 y d x + 3 x d y) + 2 x y (3 y d x + 4 x d y) = 0

x + 2 y + 4 z = 2

4 x + 3 y + z = 5

3 x + 2 y + 3 z = 1

\frac{1}{2 (2 x + 3 y)} + \frac{12}{7 (3 x - 2 y)} = \frac{1}{2}

\frac{7}{2 x + 3 y} + \frac{4}{3 x - 2 y} = 2

2 x + 3 y \neq 0

3 x - 2 y \neq 0

x + 2 y = 5

3 x + 7 y = 17

3 x + 4 y = 10

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