If (2x2+3y2):(2x2−3y2)=11:5, find the value of (5x4+7y4):(5x4−7y4).
2x2+3y22x2−3y2=115
Using componendo and dividendo
(2x2+3y2)+(2x2−3y2)(2x2+3y2)−(2x2−3y2)=11+511−54x26y2=166x2y2=41x4y4=161
Multiplying both sides by 57
5x47y4=807
Using componendo and dividendo
5x4+7y45x4−7y4=8773