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Question

If (2x2+3y2):(2x23y2)=11:5, find the value of (5x4+7y4):(5x47y4).

A

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B

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C

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Solution

The correct option is C


2x2+3y22x23y2=115
Using componendo and dividendo
(2x2+3y2)+(2x23y2)(2x2+3y2)(2x23y2)=11+51154x26y2=166x2y2=41x4y4=161
Multiplying both sides by 57
5x47y4=807
Using componendo and dividendo
5x4+7y45x47y4=8773


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