Question

If $2x^2+7xy+3y^2+8x+14y+\lambda =0$ represents a pair of straight lines, then the value of $\lambda$ is

• A. $4$
• B. $-3$
• C. $8$
• D. $6$

Answer 1

The correct option is C $8$

The equation $a{x}^2+2hxy+b{y}^2+2gx+2fy+c=0$
represents a pair of straight lines, if
$abc+2fgh-a{f}^2-b{g}^2-c{h}^2=0.$
Hence, $2x^2+7xy+3y^2+8x+14y+\lambda =0$ represents a pair of straight lines if
$6\lambda +2\left(7\right)\left(4\right)\left(\frac{7}{2}\right)-2(7{)}^2-3(4{)}^2-\lambda {\left(\frac{7}{2}\right)}^2=0$
$\Rightarrow 6\lambda +196-98-48-\frac{49\lambda }{4}=0$
$\Rightarrow \frac{49\lambda }{4}-6\lambda =196-146$
$\Rightarrow \frac{25\lambda }{4}=50$
$\Rightarrow \lambda =\frac{50\times 4}{25}=8$