If $(2 x^{2} - x - 1)^{5}$ = $a_{0} + a_{1} x + a_{2} x^{2} . . . . . . . . . . . . . . a_{10} x^{10}$ , then -( $a_{0}$ ) =

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Solution

$a_{0}$ is the constant term. To get the constant term, put x = 0

⇒ $(0 - 0 - 1)^{5} = a_{0}$

⇒ $a_{0}$ = -1

⇒ - ( $a_{0})$ = 1

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