If 2x2+xy−3y2+x+ay−10=(2x+3y+b)(x−y−2), the value of a and b are
A
11and5
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B
1 and −5
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C
−1 and −5
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D
−11 and 5
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Solution
The correct option is D−11 and 5 ∵2x2+xy−3y2+x+ay−10 =(2x+3y+b)(x−y−2) =2x2+xy−3y2+(b−4)x−(b+6)y−2b Compare the coefficients of x, y and constant on both sides, b−4=1⟹b=5 −(b+6)=a⟹a=−11 2b=10⟹b=5 ∴a=−11 and b=5