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Question

If 2x2+xy3y2+x+ay10=(2x+3y+b)(xy2), the value of a and b are

A
11 and 5
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B
1 and 5
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C
1 and 5
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D
11 and 5
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Solution

The correct option is D 11 and 5
2x2+xy3y2+x+ay10
=(2x+3y+b)(xy2)
=2x2+xy3y2+(b4)x(b+6)y2b
Compare the coefficients of x, y and constant on both sides,
b4=1b=5
(b+6)=aa=11
2b=10b=5
a=11 and b=5

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