If -2 x -3-4- x- which of the following relations hold-A- 2 x-3-4-xB- 2 x-3-x-4C- Both relations holdD- Neither relations hold

The correct option is C Both relations hold|2x 3|= 4 x ⇒ 2x 3 = 4 + x and 2x 3 = (4 x ) ⇒ 2x 3 = 4 + x and 2x 3 = x 4 Hence, C is the correct ...

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Properties of absolute values

If |2 x -3|=4...

Question

If $| 2 x - 3 | = 4 - x$ , which of the following relations hold?

2x - 3 = 4 - x

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2x - 3 = x - 4

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Both relations hold

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Neither relations hold

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lim x \to \infty \frac{a (2 x^{3} - x^{2}) + b (x^{3} + 5 x^{2} - 1) - c (3 x^{3} + x^{2})}{a (5 x^{4} - x) - b x^{4} + c (4 x^{4} + 1) + 2 x^{2} + 5 x} = 1

a

b

c

[x] = \frac{3}{2} {x}

How many real numbers satisfy the relation $[x]$ = $\frac{3}{2}$ {x}?

lim x \to \infty \frac{2 \sqrt{x} + 3 \sqrt[3]{x} + 4 \sqrt[4]{x} + . . . + n \sqrt[n]{x}}{\sqrt{(2 x - 3)} + \sqrt[3]{(2 x - 3)} + \sqrt[4]{(2 x - 3)} + . . . + \sqrt[n]{(2 x - 3)}}

A = 1, 2, 3, 4, 5

B = 1, 3, 5, 7, 9, 10, 17, 26, 30 .

R_{1}

R_{2}

R_{3} = (x, y) : x \in A, y \in B, x + y = 8

R_{4} = (x, y) : x \in A, y \in B, y = x^{2} + 1

R_{5} = (x, y) : x \in A, y \in B, y = 2 x - 1

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