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B
−1
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C
1
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D
2
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Solution
The correct option is A0 Given equations are: 2x+3y=0.....(1) 4x−3y=0.....(2) Now multiply (1) by (2) we get 4x+6y=0......(3) Now subtracting (2) from (3), we get ⇒9y=0 ⇒y=0 now substitute the y value in (3) ⇒4x+6(0)=0 ⇒4x=0 ⇒x=0 ⇒x+y=0+0 ⇒x+y=0