If 2x – 3y = 1, then express $4 x^{2} - 2 x + 3$ in terms of y.

9y² – 3y + 3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

9y² – 2y + 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

y² – 3y + 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9y² + 3y + 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
9y² – 3y + 3

$2 x - 3 y = 1 x = \frac{(1 + 3 y)}{2} 4 {(\frac{1 + 3 y}{2})}^{2} - \frac{1 + 3 y}{2 + 3} (1 + 3 y)^{2} - (1 + 3 y) + 3 9 y^{2} - 3 y + 3$

Suggest Corrections

Similar questions

2 x = 3 y + \sqrt{2 x^{2} + m}

2 x + 3 y = 1

\frac{x}{2} + \frac{y}{3}

y

\sqrt{3 - 2 x} = \sqrt{2 x} + 1

4 x^{2} =

If $y = \frac{2 x + 1}{2 x - 1}$ , we can express x in terms of y as $x = a (\frac{y + 1}{y - 1}) . F i n d \frac{1}{a}$

\frac{2 x}{3 y} = \frac{3 y}{4 z}

4 x^{2} + 9 y^{2} + 16 z^{2} = (2 x - 3 y + 4 z) (2 x + 3 y + 4 z)

Join BYJU'S Learning Program