Question

If $2x+3y=1$, what is $\frac{x}{2}+\frac{y}{3}$ in terms of $y$?

• A. $\frac{y}{5}$
• B. $\frac{1-3y}{2}$
• C. $\frac{1-3y}{4}$
• D. $\frac{3y+4}{15}$
• E. $\frac{3-5y}{12}$

Answer 1

Answer: (E)

$\frac{3-5y}{12}$

Given that, $2x+3y=1$

$\Rightarrow x=\frac{(1-3y)}{2}$.

Now $\frac{x}{2}+\frac{y}{3}$

$\Rightarrow \frac{(1-3y)/2}{2}+\frac{y}{3}$

$=\frac{1-3y}{4}+\frac{y}{3}$

$=\frac{3-5y}{12}$