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Question

If 2x - 3y3z + y= z - yz - x = x + 3z2y - 3x then prove that every ratio = xy.

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Solution


2x-3y3z+y=z-yz-x=x+3z2y-3x2x-3y3z+y=3z-y3z-x=x+3z2y-3x2x-3y3z+y=3z-y3z-x=x+3z2y-3x=2x-3y-3z-y+x+3z3z+y-3z-x+2y-3x Theorem of equal ratios
2x-3y3z+y=3z-y3z-x=x+3z2y-3x=2x-3y-3z+3y+x+3z3z+y-3z+3x+2y-3x2x-3y3z+y=3z-y3z-x=x+3z2y-3x=3x3y2x-3y3z+y=z-yz-x=x+3z2y-3x=xy

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