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Question

If 2x - 3y3z + y = z -yz - x = x + 3z2y - 3x, then show that each ratio is xy.

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Solution

Let: 2x-3y3z+y=z-yz-x=x+3z2y-3x=kBy the theorem on equal ratios, we get: k=2x-3y+z-y+x+3z3z+y+z-x+2y-3xk=3x-4y+4z3y+4z-4xOn multiplying z-yz-xby 4, we get:k=4z-4y4z-4xAgain, by the theorem on equal ratios, we get:k=3x-4y+4z-4z-4y3y+4z-4x-4z-4xk=3x3yk=xyHence, each ratio is equal to xy.

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