If (2x + iy) + (y - 3ix) = 12 - 3i, then X = _____ y = _____
3,6
(a + ib) + (c + id) = (a + c) + i (b + d)
So, (2x + iy) + (y - 3ix) = (2x + y) + I (y - 3x)
= 12 - 3i [given]
2x + y = 12 --------- (1)
-y + 3x = 3
______________________
5x = 15 x = 3
From (1) y = 12 - 2x = 6
So, x = 3, y = 6