Question

If $2x,x+10,3x+2$ are in AP. Find the value of x.

• A. 6
• B. 12
• C. $\sqrt{36}$
• D. 3

Answer 1

Answer: (A), (C)

The correct options are
A

6

C $\sqrt{36}$

Since, $2x,x+10,3x+2$ are in AP. the difference between the consecutive term will be the same ,

Hence $x+10-2x$ = $3x+2-(x+10)$

$-x+10=2x-8$

$-x-2x=-8-10$

$3x=18$
$x=6$.