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Question

If 2x+y=23 and 4xy=19; find the values of x3y and 5y2x.

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Solution

2x+y = 23. .....(1)
4x-y = 19. ......(2)

Adding (1) and (2)
2x+y = 23
4x-y=19
-----------------
6x = 42
x = 7
Now Putting x=7 in (2)
4x-y=19
4×7-y=19
28-y=19
y=28-19
y=9
So,
x-3y=7-3×9 =7-27 = -20
x-3y=-20

Again,
5y-2x=5×9-2×7 =45-14 = 31
5y-2x = 31


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