Question

If $2x+y=9$ and $3x-y=6$ then find the value of $x$.

Answer 1

Given,

$2x+y=9$--------------------------$\left(1\right)$

$3x-y=6$--------------------------$\left(2\right)$

Adding $e{q}^n\left(1\right)$ and $e{q}^n\left(2\right)$

$2x+y=9$ $+$ $(3x-y=6)$ $=9+6$

$x=\frac{15}{5}=3$

We get, $x=3$