Question

If $3(2-x)\ge 2(1-x)$ and $x\in R$, then $x\in$

• A. $(-\infty ,\frac{4}{5}]$
• B. $[4,\infty )$
• C. $(-\infty ,4)$
• D. $(-\infty ,4]$

Answer 1

The correct option is D $(-\infty ,4]$

$3(2-x)\ge 2(1-x)$
$\Rightarrow 6–3x\ge 2–2x$
$\Rightarrow 4\ge x$
$\Rightarrow x\le 4$