If (3−5i)3 can be expressed in the form a+ib ,then the ordered pair (a,b) is
A
(−198,10)
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B
(−198,−10)
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C
(198,−10)
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D
(198,10)
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Solution
The correct option is B(−198,−10) We know that (z1−z2)3=z31−z32−3z1z2(z1−z2). ∴(3−5i)3=33−(5i)3−3×3×5i(3−5i) =27−125i3−135i+225i2 =27+125i−135i−225∵[i3=−i,i2=−1] =−198−10i.