If 3 - 5i is one root of the equation - x2 + ax + b = 0, find a + b, where a,b∈ R
-28
Complex roots occur in conjugate pairs.
Since the coefficients are all real, the other root will be conjugate of 3 - 5i i.e. 3 + 5i
Sum of roots = 3 - 5i + 3 + 5i
−a−1 = 6
⇒ a = 6
Products of roots = (3 - 5i) × (3 + 5i)
b−1 = 9 + 25
b = - 34
a+b= -28