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Question

If 3 - 5i is one root of the equation - x2 + ax + b = 0, find a + b, where a,b∈ R


  1. 24

  2. -34

  3. -28

  4. 34


Solution

The correct option is C

-28


Complex roots occur in conjugate pairs.

Since the coefficients are all real, the other root will be conjugate of 3 - 5i i.e. 3 + 5i

Sum of roots = 3 - 5i + 3 + 5i

a1 = 6

  ⇒ a = 6

Products of roots =  (3 - 5i) × (3 + 5i)

b1 = 9 + 25 

b = - 34

a+b= -28

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