Question

If $3-5x$ is less than or equal to $8$, then the minimum value of $x$ will be

Answer 1

Given algebraic inequality : $3-5x\le 8$
Subtract $3$ from both sides of inequality
$\Rightarrow 3-5x-3\le 8-3$
$\Rightarrow -5x\le 5$
Divide both sides of inequality by $-5$
$\Rightarrow \frac{-5x}{-5}\ge \frac{5}{-5}$
$\Rightarrow x\ge -1$
Minimum value of $x$ is $-1$.