If $3.65$ g of $H C l$ is dissolved in $16.2$ g of water then the mole fraction of $H C l$ ?

0.2

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0.1

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0.3

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0.4

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Solution

The correct option is A $0.1$
Moles of $H C l = 3.65 / 36.5 = 0.1$
Moles of $H_{2} O = 16.2 / 18 = 0.9$
Total moles= $0.1 + 0.9 = 1.0$
$∴$ Mole fraction of $H C l = \frac{0.1}{1} = 0.1$

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