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Question

If 3[xyzw]=[x612w]+[4x+yz+w3], find the values of x,y,z & w.

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Solution

3[xyzw]=[x612w]+[4x+yz+w3]
[3x3y3z3w]=[x+46+x+yz+w13+2w]
3y=x+y+6
x=2
3y=x+y+6
2y=x+6
y=4
3w=3+2w
w=3
3z=w+z1
z=1
x=2,y=4,z=1,w=3

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