Question

If $3$ coins are tossed simultaneously, the probability of $1$ head and $2$ tails is:

• A. $\frac{1}{8}$
• B. $\frac{3}{8}$
• C. $\frac{5}{8}$
• D. $\frac{7}{8}$

Answer 1

Answer: (B)

$\frac{3}{8}$

Given: Coin tossed $3$ times

To find: The probability of $1$ heads and $2$ tail

According to the question, $n\left(S\right)=2^3=8$

Favourable ways to get $1$ head and $2$ tails are $\{HTT,THT,TTH\}$

Hence, the probability of getting $1$ head and $2$ tails $=\frac{3}{8}$