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Question

If 3cosA=4sinA, the value of cosA is m5, m is

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Solution

3cosA=4sinA
tanA=34
tanA=PB=34
P=3,B=4
By Pythagoras Theorem,
H2=P2+B2
H2=32+42
H2=9+16
H=5
cosA=BH=45

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