If $3 cos A = 4 sin A$ , then $tan A = . . . . . .$

\frac{3}{5}

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\frac{3}{2}

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\frac{4}{3}

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\frac{3}{4}

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Solution

The correct option is D $\frac{3}{4}$
$3 c o s A = 4 sin A \Rightarrow \frac{3}{4} = \frac{sin A}{cos A} \Rightarrow \frac{3}{4} = tan A$

Therefore, Answer is $\frac{3}{4}$

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