If 3 dice are rolled then, what is the probability that the sum is 16

\frac{7}{12}

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\frac{5}{36}

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\frac{2}{9}

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\frac{1}{36}

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Solution

The correct option is D $\frac{1}{36}$
3 dice are rolled total outcomes=666
For sum to be 16 favourable outcomes are (4,6,6),(6,4,6),(6,6,4),(5,5,6),(6,5,5),(5,6,5)=6
Probability that the sum is 16=6/666*=1/36

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Similar questions

Event: 'Sum on $2$ dice'	$2$	$3$	$4$	$5$	$6$	$7$	$8$	$9$	$10$	$11$	$12$
Probability	$\frac{1}{36}$						$\frac{5}{36}$				$\frac{1}{36}$

11

2, 3, 4, 5, 6, 7, 8, 9, 10, 11

12

\frac{1}{11}

5

1, 2, 3, 5, 7

11,

8

\begin{matrix} Event: Sum of 2 dice & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 Probability & \frac{1}{36} & \frac{5}{36} & \frac{1}{36} \end{matrix}

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