If 3(log9x)2−92log9x+5=3√3, then possible value(s) of x is/are
A
9
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B
37/2
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C
37
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D
35/2
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Solution
The correct options are A9 C37 3(log9x)2−92log9x+5=3√3 Taking log on both sides to the base 3, we get (log9x)2−92log9x+5=32 Put y=log9x y2−92y+5=32⇒2y2−9y+7=0 ⇒(2y−7)(y−1)=0 ⇒y=72,1 ⇒log9x=1 or log9x=72 ⇒x=9 or x=97/2=37