If $3^{n}$ = 27, then $3^{n - 2}$ is

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Solution

The correct option is C 3
Given $3^{n} = 27$

$\Rightarrow n = 3$

$\Rightarrow 3^{n - 2} = 3^{3 - 2} = 3$

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Similar questions

3^{n} = 27

3^{n - 2}

If 3 $^{n}$ = 27 , then 3 $^{n - 2}$ is

n \sum r = 1 T_{r} = (3^{n} - 1),

n \sum r = 1 \frac{1}{T_{r}}

C_{0} + \frac{3}{2} . C_{1} + C_{2} + \frac{27}{4} . C_{3} + + \frac{3^{n}}{n + 1} . C_{n} = \frac{4^{n + 1} + 1}{3 (n + 1)}

{(1 + x + x^{2})}^{n} = \sum_{r = 0}^{2} a_{r} x^{r} t h e n a_{0} + a_{4} \dots + a_{2 n}

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