Question

If $3percent$ bulb manufactured by a company are defective; the probability that in a sample of $100$ bulbs exactly five defective is

• A. $\frac{e^{-0.003}{\left(0.03\right)}^5}{5!}$
• B. $\frac{e^{-0.3}{0.03}^5}{5!}$
• C. $\frac{e^{-3}{3}^5}{5!}$
• D. $\frac{e^{-0.3}{3}^{-5}}{5!}$

Answer 1

The correct option is C $\frac{e^{-3}{3}^5}{5!}$

$Inpoisondistribution\frac{e^{-u}{u}^x}{x!}Here3aredefectivein100sou=3Probailitythatexactly5aredefective(x=5)=\frac{e^{-3}{\left(3\right)}^5}{5!}$