If 3sinα=5sinβ, then tanα+β2tanα−β2 is equal to
2sin(α+β2)cos(α−β2)2sin(α−β2)cos(α+β2)=4
tan(α+β2)tan(α−β2)=4
If 5 sin α=3 sin (α+2β)≠0, then the tan(α+β) is equal to