If 3sin-5sin- then tan- -2-tan-2-

The correct option is D 4 3sinα=5sinβ ⇒sinα/sinβ=5/3 ⇒sinα+sinβ/sinα sinβ=5+3/5 3 ⇒2sinα+β2cosα β22cosα+β2sinα β2=82 ⇒tanα+β2tanα β2=4 ...

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Domain and Range of Basic Inverse Trigonometric Functions

If 3sinα=5s...

Question

If $3 sin α = 5 sin β$ , then $\frac{tan \frac{α + β}{2}}{tan \frac{α - β}{2}} =$

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Solution

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Similar questions

3 sin α = 5 sin β

tan (\frac{α + β}{2}) + tan (\frac{α - β}{2})

3 s i n α = 5 s i n β

\frac{tan \frac{α + β}{2}}{tan \frac{α - β}{2}}

If 5 sin $α = 3 s i n (α + 2 β) \neq 0$ , then the $t a n (α + β)$ is equal to

5 \sin α = 3 \sin (α + 2 β) \neq 0

\tan (α + β)

2 \tan β

3 \tan β

4 \tan β

6 \tan β

0 \leq α, β \leq 90

tan (α + β) = 3

tan (α - β) = 2

sin 2 α

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