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Basic Inverse Trigonometric Functions

If 3sinα =5...

Question

If $3 sin α = 5 sin β$ , then: $tan (\frac{α + β}{2}) + tan (\frac{α - β}{2})$ .

A

1

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B

2

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C

3

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D

4

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Solution

The correct option is D $4$

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Similar questions

3 sin α = 5 sin β

\frac{tan \frac{α + β}{2}}{tan \frac{α - β}{2}} =

3 s i n α = 5 s i n β

\frac{tan \frac{α + β}{2}}{tan \frac{α - β}{2}}

tan (α + β) = \sqrt{3}, tan (α - β) = 1

4 β =

If 5 sin $α = 3 s i n (α + 2 β) \neq 0$ , then the $t a n (α + β)$ is equal to

5 \sin α = 3 \sin (α + 2 β) \neq 0

\tan (α + β)

is equal to
(a)

2 \tan β

3 \tan β

4 \tan β

6 \tan β

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