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Question

If 3sinx+4cosax=7 has atleast one solution, then 'a' has to be necessarily _______.


A
irrational number
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B
rational number
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C
even integer
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D
odd integer
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Solution

The correct option is B rational number
3sinx+4cosax=7sinx=1, cosax=1x=(4n1+1)π2,ax=2n2π, n1,n2Z(4n1+1)π2=2n2πaa=4n24n1+1
It is a rational number.

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