Question

If $-3+x^{2}yi$ and $x^2+y+4i$are conjugate complex numbers, then x =

• A. 0
• B. ±1
• C. ±2
• D. ±3

Answer 1

The correct option is B

±1

$-3+x^{2}yi=x^2+y-4i$
$\Rightarrow x^2+y=-3,x^{2}y=-4\Rightarrow y=\frac{-4}{{\lambda }^2}$
$\Rightarrow x^2-\frac{4}{x^2}+3=0\Rightarrow x^4+3x^2-4=0$
$\Rightarrow x^2=1\Rightarrow x=\pm 1$